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高二物理-平面運動高手請幫忙

Oct 3rd 2013, 13:05

自地面以初速v0＝40公尺/秒，仰角θ射出一子彈，恰可越過距拋射點40公尺而高度70公尺之塔頂，設空氣阻力不計，且g＝10公尺/秒2，則tan 等於　(A)1　(B) 　(C)2　(D)3　(E)2 。
(方法一)
答案：D
解析：計算
由y＝x tanθ－gx^2/v0^2cos^2θ ------> 70＝40 tanθ－10x40^2/2x40^2 ×（1＋tan^2θ）　解之可得

除了以上(方法一)算法有沒有其他算法

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