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| 徵求五權西與向心路口車禍之影帶或目擊者
Jun 29th 2013, 09:07
有哪位大大可以提供6月25日下午4點至5點台中市五權西路與向上路口監視錄影器或行車紀錄影器影像?弟弟騎機車返家於下班時間於上述時間地點出車禍,有一部銀色豐田VIOS行進時突然剎車,弟弟騎車閃避不及撞上該車,而人車倒地,並且左腳膝蓋粉碎性骨折,該車於車禍後不但未下車關切,反而加速逃逸,以致於未記下該車號,如有人於上述時間地點曾目睹車禍現場過程,請將線索提供0972674029莊警官,謝謝!!
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| [問題] 請問有人也在等長春面試嗎？
Jun 28th 2013, 18:13, by bukkieT
作者bukkieT (BT)
看板Salary
標題[問題] 請問有人也在等長春面試嗎？
時間Fri Jun 28 18:13:15 2013
五月底接到長春面試通知，但在面試前一天突然取消並說會再通知。 因為知道長春拒絕人快、狠、準XD 所以月中還沒收到後續消息就打電話去問，想說如果掰掰至少也得到一個答案。 但蔣先生說目前還沒有進一步消息，所以我又回到了原點... 想請問有人也在等嗎？或是之前有沒有人也遇過這樣的狀況？大概會等多久呢？ 如果不方便在版上回覆，也可以私信給我...真的很想進長春啊 T^T 謝謝！ -- Sent from my Android -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 115.80.112.132
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| 工程數學3題求詳解
Jun 28th 2013, 14:37
1.y"'+3y"-4y=0
輔助方程式:
0=D^3+3D^2-4=(D-1)(D+2)^2
D=1,-2,-2
So y(x)=(c1+c2*x)*e^(-2x)+c3*e^x
2.y"-10y'+25y=30x+3
輔助方程式:
0=D^2-10D+25=(D-5)^2
D=5,5
齊次解: yh(x)=(c1+c2*x)*e^(5x)
設特殊解:
yp(x)=a*x^2+bx+c => 25yp=25a*x^2+25bx+25c
yp'=2ax+b => -10yp=-20ax-10b
yp"=2a
Add: 30x+3=25ax^2+(25b-20a)x+(25c-10b+2a)
a=0, 25b-20a=30 => b=6/5
25c-10b+2a=3 => c=3/5
So yp(x)=(2x+1)3/5
通解: y(x)=yh(x)+yp(x)=(c1+c2*x)*e^(5x)(2x+1)3/5
3.IF F=(x^2*y^3-z^4)i+(4x^5*y^2*z)j-(y^4*z^6)k, find
(a)curl(F)
=|∂/∂y ..........∂/∂z .....∂/∂x ..........∂/∂y........|
.|(4x^5*y^2*z) -(y^4*z^6) (x^2*y^3-z^4) (4x^5*y^2*z)|
=(-4y^3*z^6-4x^5*y^2; -4z^3+0; 20x^4*y^2*z-3x^2*y^2)
=-4y^2(y*z^6+x^5)i-4z^3j+x^2*y^2(20x^2+3)k
(b)div(F)
=∂Fx/∂x+∂Fy/∂y+∂Fz/∂z
=2xy^3+8x^5*yz-6y^4*z^5
=2y(xy^2+4x^5*z-3y^3*z^5)
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