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| [贈送] 畢業雜物
Jun 28th 2013, 16:01
作者whatiwant (我想要)
看板give
標題[贈送] 畢業雜物
時間Fri Jun 28 16:01:01 2013
物 品： 1mm厚紙板*1捲 鼠籠+一些用品 單面計算紙*15cm厚 耳機*1 簡易耳麥*1 到期日(食品及美妝品請加上到期日): 領取地點：台南市裕豐街7-11 地圖: http://goo.gl/maps/8Qa3E 期 限：送出為止 聯絡方法：站內信 備 註： -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 61.227.243.66
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| Yahoo!奇摩知識+ - 分類問答 - 科學常識 - 已解決 |
| Yahoo!奇摩知識+ - 分類問答 - 科學常識 - 已解決 |
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| 線性代數特徵值特徵向量求解
Jun 28th 2013, 17:29
設
[1 2 1 ]
[0 3 1 ] = A
[0 5 -1]
則
[k-1 -2 -1 ]
[ 0 k-3 -1 ] = kI - A
[ 0 -5 k+1]
設| kI-A | = 0
(k-1)[(k-3)(k+1)-5] = 0
(k-1)(k^2 -2k -8) = 0
(k-1)(k-4)(k+2) = 0
k= -2, 1 或 4
設 k1= -2, k2= 1, k3= 4, v1, v2, v3分別為對應k1, k2, k3的特徵向量
設
[x1]
[y1] = vi , i=1,2,3
[z1]
考慮v1,
[1 2 1 ][x1] [x1]
[0 3 1 ][y1] = -2 [y1]
[0 5 -1][y1] [z1]
得
x1+2y1+z1 = -2x1
3y1+z1 = -2y1
5y1 - z1 = -2z1
其中一解為:
[ 1 ]
[ 1 ] = v1
[ -5 ]
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| udn日韓星情 |
| udn日韓星情：提供聯合報系影視新聞，內容包括日韓明星娛樂情報、最新動態。 |
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| 女兒男友協調 黛咪摩兒母女和解
Jun 28th 2013, 19:16
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同是卡巴拉教友的好姊妹黛咪摩兒與瑪丹娜，與子女的關係大不同：黛咪一度和3個女兒鬧翻、疏遠，但在大女...
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